It would seem that to reveal the dependence of voltage on frequency is simple. One has only to apply to the all-knowing search engines with a corresponding request and ... make sure that there is simply no answer to this question. What to do? Let's figure it out together on this difficult issue.
Voltage or potential difference?
It should be noted that voltage and potential difference are one and the same. In fact, it is a force that can cause electric charges to flow. It does not matter where this movement will be directed.
The potential difference is just another expression for voltage. It is more visual and, perhaps, more understandable, but does not change the essence of the matter. Therefore, the main question is where the voltage comes from and what it depends on.
As for the 220 Volt home network, the answer is simple. At a hydroelectric station, a water stream rotates the generator rotor. The energy of rotation is transformed into a force of tension. A nuclear power plant first turns water into steam. He twists the turbine. In a gas power plant, the rotor rotates the power of burning gasoline. There are other sources, but the essence is always the same: energy turns into tension.
It's time to wonder about the dependence of voltage on frequency. But we still don't know where the frequency comes from.
What is the source of frequency
The same generator. The frequency of its rotation turns into the same property of voltage. Rotate the generator faster - the frequency will be higher. And vice versa.
The tail cannot wag the dog. For the same reason, the frequency cannot change the voltage. Therefore, the expression "voltage dependence of the current frequency" does not make sense?
To find the answer, you need to correctly formulate the question. There is such a saying about a fool and 10 learned men. He asked the wrong questions, but they could not answer.
If you call stress another definition, everything will fall into place. It is used for circuits consisting of many different resistances. "Voltage drop". Both expressions are often considered synonyms, which is almost always wrong. Because the voltage drop can really depend on the frequency.
Why would the voltage drop?
Yes, simply because it cannot fail to fall. So. If at one pole of the source the potential is 220 volts, and at the other - zero, then this drop could only occur in the circuit. Ohm’s law says that if there is one resistance in the network, then all the voltage on it will drop. If two or more, each drop will be proportional to its value, and their sum is equal to the initial potential difference.
So what? Where is the indication of voltage versus current frequency? So far, everything depends on the magnitude of the resistance. Now, if you find a resistor that changes its parameters when the frequency changes! Then the voltage drop on it would change automatically.
There are such resistors
They are also called reactive, in contrast to active counterparts. What do they react to by changing their size? To the frequency! There are 2 types of reactance:
Each species is associated with its own field. Inductive - with magnetic, capacitive - with electric. In practice, they are represented primarily by solenoids.
They are presented in the photo above. And capacitors (below).
They can be considered antipodes, because the reaction to a change in frequency is directly opposite. Inductance increases with frequency. Capacitive, on the contrary, falls.
Now, given the characteristics of reactance, in accordance with Ohm's law, it can be argued that the dependence of voltage on the frequency of the alternating current exists. It can be calculated taking into account the values of reactance in the circuit. Only for clarity, we must remember that we are talking about the voltage drop on the circuit element.
And yet it exists!
The question mark in the article title turned into an exclamation point. Yandex rehabilitated. It remains only to give formulas for the dependence of voltage on frequency for different types of reactance.
Capacitive: XC = 1 / (wC). Here w is the angular frequency, C is the capacitance of the capacitor.
Inductive: XL = w · L, where w is the same as in the previous formula, L is the inductance.
As you can see, the frequency affects the magnitude of the resistance, changing it, therefore, changes the voltage drop. If the network has an active resistance R, capacitive XC and inductive XL, then the sum of the voltage drops on each element will be equal to the potential difference of the source: U = U r + U xc + U xl .